[LintCode] Reverse Array（翻转数组）

原地翻转给出的数组 nums

给出 nums = [1,2,5]
返回 [5,2,1]

代码

/**
 * 767 https://www.lintcode.com/problem/reverse-array/description
 */
@Test
public void testReverseArray() {
  int[] nums = { 1, 2, 3, 4, 5, 6, 7 };

  for (int i = 0; i < nums.length / 2; i++) {
    int tmp = nums[i];
    nums[i] = nums[nums.length - 1 - i];
    nums[nums.length - 1 - i] = tmp;
  }

  System.out.println(Arrays.toString(nums));

}